paulmoosberg
10-18-2006, 06:46 PM
Declare:
X=2, N=1
Loop:
(X+1) ^3 - X^3 + 150N = (X+6) ^3 - (X+5) ^3
X=X+5
N=N+1
i was stumbling across powers of 3 (cubes) and found an intricate association. i imagine if there is an aspy that likes math then they will be able to identify with my findings. and in such i was wondering if it actually works? or maybe i am seeing it wrong inside my head? don't mind the poem if you don't want to. i tend to express myself inside my poetry.
Five Grouped Cubes
The last and vast digits of change start to run
In groups it loops seven nine seven one one
The nines can shine that an off pattern is spun
In groups of troops between nine and seven’s son
Then cube the tube if X has seven or two
Inside to hide X’s last digit’s value
Then count amount to times as the five’s debut
Inside this stride minus six from five to view
A two to do as X N as one to state
Loop (Next of X) cube minus X cube plus fate
One fifty lifted by N to show its trait
Cube on (six) dawn (five) then X and N update
Declare:
X=2, N=1
Loop:
(X+1) ^3 - X^3 + 150N = (X+6) ^3 - (X+5) ^3
X=X+5
N=N+1
the trick is this:
1^3=1, 2^3=8, 3^3=27, 4^3=64, 5^3=125, 6^3=216, 7^3=343, 8^3=512, 9^3=729, 10^3=1000, 11^3=1331
now if you take the difference of the adjacent (next to eah other) cubes then there is a pattern in that last digit of the difference between. the pattern is 79711 so it is a group of five differences that repeats and always does 79711 as the last digit of the answer. ie the differences from example above:
7,19,37,61,91,127,169,217,271,331
see last digits are 79711 repeating always
well the cubes that make the pattern of the last digits as 9 can caculate a later power of +6 to the lower of the 2 cubes that are adjacent in the examples at the top. but funny enough the cubes that are producing the difference with a last digit of 9 are ending in 2 or 7 since the grouping of this pattern 79711 is a group of five.
then i put the counter in to show the derivations or what ever, but the difference of the difference ups by 150 evey 5 cubes so this gave me a way to calculate what the 2nd or the 3rd in the next group by flopping the opposing to the other side of the equal sign with some different math to them. but the basis is that i can calculate the numbers cubed if the numbers being cubed end in 2 or 7.
it's kinda funny that it works cause it is really wierd to see it in my head like spinning spirals of math and color.
i made an excell spreadshet and calculated out to like 102 cubes and the math still works. maybe someone can tell me the name of what i stumbled on? probably something to do with the law of cubes i would imagine.
X=2, N=1
Loop:
(X+1) ^3 - X^3 + 150N = (X+6) ^3 - (X+5) ^3
X=X+5
N=N+1
i was stumbling across powers of 3 (cubes) and found an intricate association. i imagine if there is an aspy that likes math then they will be able to identify with my findings. and in such i was wondering if it actually works? or maybe i am seeing it wrong inside my head? don't mind the poem if you don't want to. i tend to express myself inside my poetry.
Five Grouped Cubes
The last and vast digits of change start to run
In groups it loops seven nine seven one one
The nines can shine that an off pattern is spun
In groups of troops between nine and seven’s son
Then cube the tube if X has seven or two
Inside to hide X’s last digit’s value
Then count amount to times as the five’s debut
Inside this stride minus six from five to view
A two to do as X N as one to state
Loop (Next of X) cube minus X cube plus fate
One fifty lifted by N to show its trait
Cube on (six) dawn (five) then X and N update
Declare:
X=2, N=1
Loop:
(X+1) ^3 - X^3 + 150N = (X+6) ^3 - (X+5) ^3
X=X+5
N=N+1
the trick is this:
1^3=1, 2^3=8, 3^3=27, 4^3=64, 5^3=125, 6^3=216, 7^3=343, 8^3=512, 9^3=729, 10^3=1000, 11^3=1331
now if you take the difference of the adjacent (next to eah other) cubes then there is a pattern in that last digit of the difference between. the pattern is 79711 so it is a group of five differences that repeats and always does 79711 as the last digit of the answer. ie the differences from example above:
7,19,37,61,91,127,169,217,271,331
see last digits are 79711 repeating always
well the cubes that make the pattern of the last digits as 9 can caculate a later power of +6 to the lower of the 2 cubes that are adjacent in the examples at the top. but funny enough the cubes that are producing the difference with a last digit of 9 are ending in 2 or 7 since the grouping of this pattern 79711 is a group of five.
then i put the counter in to show the derivations or what ever, but the difference of the difference ups by 150 evey 5 cubes so this gave me a way to calculate what the 2nd or the 3rd in the next group by flopping the opposing to the other side of the equal sign with some different math to them. but the basis is that i can calculate the numbers cubed if the numbers being cubed end in 2 or 7.
it's kinda funny that it works cause it is really wierd to see it in my head like spinning spirals of math and color.
i made an excell spreadshet and calculated out to like 102 cubes and the math still works. maybe someone can tell me the name of what i stumbled on? probably something to do with the law of cubes i would imagine.